UP High Court RO / ARO 06 Jan 2022 Shift 1

What is the maximum number of whole laddoos having diameter of 6 cm that can be packed in a box, whose inner dimensions are $24 \text{ cm} \times 18 \text{ cm} \times 17 \text{ cm}$?

Verified Answer
A. 24
B. 30
C. 33
D. 36

Explanation:

To find the maximum number of whole laddoos that can be packed, we need to consider how many laddoos fit along each dimension of the box. Since laddoos are spherical, when packed, each laddoo effectively occupies a cube with side length equal to its diameter. \nGiven:\nDiameter of each laddoo = $6 \text{ cm}$\nBox dimensions: Length ($L$) = $24 \text{ cm}$, Width ($W$) = $18 \text{ cm}$, Height ($H$) = $17 \text{ cm}$ \nCalculate the number of laddoos that can fit along each dimension: 1. **Along the Length ($L$):** Number of laddoos ($N_L$) = $\lfloor \frac{\text{Box Length}}{\text{Laddoo Diameter}} \rfloor = \lfloor \frac{24 \text{ cm}}{6 \text{ cm}} \rfloor = \lfloor 4 \rfloor = 4$ laddoos. 2. **Along the Width ($W$):** Number of laddoos ($N_W$) = $\lfloor \frac{\text{Box Width}}{\text{Laddoo Diameter}} \rfloor = \lfloor \frac{18 \text{ cm}}{6 \text{ cm}} \rfloor = \lfloor 3 \rfloor = 3$ laddoos. 3. **Along the Height ($H$):** Number of laddoos ($N_H$) = $\lfloor \frac{\text{Box Height}}{\text{Laddoo Diameter}} \rfloor = \lfloor \frac{17 \text{ cm}}{6 \text{ cm}} \rfloor = \lfloor 2.833... \rfloor = 2$ laddoos. (We take the floor value because only whole laddoos can be packed). \nTo find the total maximum number of whole laddoos, multiply the number of laddoos along each dimension:\nTotal Laddoos = $N_L \times N_W \times N_H = 4 \times 3 \times 2 = 24$ laddoos. \nLet's analyze the options:\nOption (A) $24$: This matches our calculated maximum number of whole laddoos. This is correct.\nOption (B) $30$: This would require fitting more laddoos along one or more dimensions than possible (e.g., $5 \times 3 \times 2 = 30$, which implies fitting 5 along length, but only 4 fit). This is incorrect.\nOption (C) $33$: This is incorrect. It's not achievable with the given dimensions.\nOption (D) $36$: This would imply fitting $4 \times 3 \times 3 = 36$ laddoos, which means 3 laddoos along the height, but only 2 fit ($17 \text{ cm} / 6 \text{ cm} = 2.833...$). This is incorrect. \nTherefore, the correct option is (A).