Explanation:

To find the odd one out, we need to examine the properties of each number. \nStep 1: Analyze each number for common mathematical properties such as divisibility, perfect squares/cubes, or sum of digits. \nOption A: $136$ - Not a perfect square ($11^2=121, 12^2=144$). - Not a perfect cube ($5^3=125, 6^3=216$). - Divisibility: $136 = 8 \times 17$. It is a multiple of $17$. - Sum of digits: $1+3+6 = 10$. \nOption B: $102$ - Not a perfect square ($10^2=100, 11^2=121$). - Not a perfect cube ($4^3=64, 5^3=125$). - Divisibility: $102 = 6 \times 17$. It is a multiple of $17$. - Sum of digits: $1+0+2 = 3$. \nOption C: $121$ - This is a perfect square: $11^2 = 121$. - Not a perfect cube. - Divisibility: $121$ is not a multiple of $17$ ($121 \div 17 \approx 7.11$). - Sum of digits: $1+2+1 = 4$. \nOption D: $153$ - Not a perfect square ($12^2=144, 13^2=169$). - Not a perfect cube ($5^3=125, 6^3=216$). - Divisibility: $153 = 9 \times 17$. It is a multiple of $17$. - Sum of digits: $1+5+3 = 9$. \nStep 2: Identify the common property and the outlier.\nNumbers $136$, $102$, and $153$ are all multiples of $17$. $136 = 17 \times 8$ $102 = 17 \times 6$ $153 = 17 \times 9$\nNumber $121$ is not a multiple of $17$. Instead, it is a perfect square ($11^2$). \nTherefore, $121$ is the odd one out.