UP High Court RO / ARO 10 Dec 2021 Shift 1

Three of the following numbers are similar and one is different. Find the odd one out. (1) 12 (2) 14 (3) 56 (4) 20

Verified Answer
A. 12
B. 14
C. 56
D. 20

Explanation:

We need to identify the number that is different from the other three based on a common property. Let's examine the divisibility of each number by $4$: Option (1) $12$: $12 \div 4 = 3$. So, $12$ is a multiple of $4$. Option (2) $14$: $14 \div 4 = 3.5$. So, $14$ is not a multiple of $4$. Option (3) $56$: $56 \div 4 = 14$. So, $56$ is a multiple of $4$. Option (4) $20$: $20 \div 4 = 5$. So, $20$ is a multiple of $4$. Based on this analysis, numbers $12$, $56$, and $20$ are all multiples of $4$. However, $14$ is not a multiple of $4$. Therefore, $14$ is the odd one out. Options (1) $12$, (3) $56$, and (4) $20$ are similar because they are all divisible by $4$.