UP High Court RO / ARO 10 Dec 2021 Shift 1

Three of the following terms are similar. Find the odd one out. (1) SO (2) ME (3) PL (4) KG

Verified Answer
A. SO
B. ME
C. PL
D. KG

Explanation:

To find the odd one out, we analyze the relationship between the letters in each pair based on their alphabetical positions (A=1, B=2, ..., Z=26). For SO: S is the $19^{\text{th}}$ letter, O is the $15^{\text{th}}$ letter. The difference is $19 - 15 = 4$. For ME: M is the $13^{\text{th}}$ letter, E is the $5^{\text{th}}$ letter. The difference is $13 - 5 = 8$. For PL: P is the $16^{\text{th}}$ letter, L is the $12^{\text{th}}$ letter. The difference is $16 - 12 = 4$. For KG: K is the $11^{\text{th}}$ letter, G is the $7^{\text{th}}$ letter. The difference is $11 - 7 = 4$. We observe that in options (1) SO, (3) PL, and (4) KG, the difference between the alphabetical positions of the two letters is $4$. However, in option (2) ME, the difference is $8$. Therefore, ME is the odd one out. Options (1) SO, (3) PL, and (4) KG are similar with a consistent difference of $4$ between their letter positions.